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  1. Hace 4 días · 0. Hola a todos tengo un if con resultados pero yo quiero agragar otro if dentro de el ejemplo. codpublix sera de 5 diferentes de codigo. introducir el código aquí. let publix = (this.customers[0].id); let codpublix = ('b1d37b65-3c20-46da-ebbf-08dc3e01e0aa');

  2. Hace 5 días · Then, we use CASE with WHEN and THEN to input remarks based on the grade column. For example, if the grade column has the value A+, then the remarks in the grade_remarks column will be Super. 3. Using IIF () We can also use the IIF () function to perform IF-THEN logic in SQL and MySQL with slight syntax modification.

  3. Hace 5 días · 1. Overview. In this tutorial, we’re going to demonstrate how to implement if/else logic with Java 8 Streams . As part of the tutorial, we’ll create a simple algorithm to identify odd and even numbers. We can take a look at this article to catch up on the Java 8 Stream basics. 2. Conventional if/else Logic Within forEach ()

  4. Hace 5 días · The IF Function is among Excel’s most commonly used, allowing you to create logical comparisons between a given number and a choice of two conditions: True or False. As before, our example contains three columns of data and a fourth for results. STEPS: Select E5 and enter the following formula:

  5. Hace 1 día · x = lambda n: n**2 if n%2 == 0 else n**3 print(x(4)) print(x(3)) The output will be 16 27 With this, we come to the end of this module in Python Tutorial . Here, we have discussed Python conditional statements, if condition in Python, if elif Else Python, nested if statement in Python, shorthand if condition in Python, and Python ...

  6. Hace 4 días · 3. Entrada de datos: Se solicita al usuario que ingrese el valor del radio del círculo mediante el mensaje "Ingrese el radio del círculo:" y se almacena este valor en la variable radio. 4. Cálculo del área: Se calcula el área del círculo utilizando la fórmula área = pi * radio^2.

  7. Hace 2 días · Solution and Explanation. The correct answer is (D) : 24. a +6d = 3 ....................... (1) Z = a(a +3d) = (3−6d)(3−3d) = 18d2 − 27d+ 9. Differentiating with respect to d. ⇒ 36d −27 = 0. ⇒ d = 43, from (1)a = 2−3,(Z = minimum ) Now, S a = 2n (−3+ (n− 1)43) = 0. ⇒ n = 5. Now, n!− 4an(n+2) = 120 −4(a35) = 120 −4(a +(35− 1)d)