Yahoo Search Búsqueda en la Web

Resultado de búsqueda

  1. Grand Duchess Maria Alexandrovna of Russia (Russian: Марія Александровна; 17 October [O.S. 5 October] 1853 – 24 October 1920) was the fifth child and only surviving daughter of Alexander II of Russia and Marie of Hesse and by Rhine; she was Duchess of Edinburgh and later Duchess of Saxe-Coburg and Gotha as the wife of Alfred ...

  2. Grand Duchess Maria Alexandrovna of Russia ( Russian: Марія Александровна; 17 October [ O.S. 5 October] 1853 – 24 October 1920) was the fifth child and only surviving daughter of Alexander II of Russia and Marie of Hesse and by Rhine; she was Duchess of Edinburgh and later Duchess of Saxe-Coburg and Gotha as the wife of Alfred, Duke of Saxe-Cobu...

  3. 13 de may. de 2020 · The present article describes the life of the Grand Duchess Maria Alexandrovna of Russia (1853–1920) through the correspondence with her parents: the Emperor of Russia Alexander II, the Empress and close friends.

    • Hélène Kolosovich
    • 2020
  4. Prince Alfred, Queen Victoria’s second son, became engaged to Grand Duchess Maria Alexandrovna, daughter of Russian Emperor Alexander II on 11 July 1873. His mother had misgivings about the match, which she wrote about in her diary: Felt quite bewildered.

    • Grand Duchess Maria Alexandrovna of Russia wikipedia1
    • Grand Duchess Maria Alexandrovna of Russia wikipedia2
    • Grand Duchess Maria Alexandrovna of Russia wikipedia3
    • Grand Duchess Maria Alexandrovna of Russia wikipedia4
    • Grand Duchess Maria Alexandrovna of Russia wikipedia5
  5. Grand Duchess Maria Alexandrovna, Duchess of Edinburgh (1853-1920) signed & dated 1876. RCIN 2092. Download image. In her life, the Duchess had the distinction of being a Russian grand duchess (by birth), a British princess and royal duchess (by marriage), and the consort (and later widow) of a German sovereign duke.

  6. Grand Duchess Maria Alexandrovna of Russia primary name: Maria Alexandrovna other name: (Duchess of) Saxe-Coburg and Gotha