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29 de may. de 2015 · Given the sequence 123456789: You can insert three operations (+ +, − −, × ×, / /) into this sequence to make the equation = 100. My question is: is there a way to solve this without brute force? (I tried to represent it as a graph but I'm unsure where to go from there.) With brute force: 123 − 45 − 67 + 89 = 100 123 − 45 − 67 ...
20 de may. de 2013 · The only break in the pattern is when you get to the digit '0' - subtracting 0 from 10 leaves you with 10, or a '1' in the next digit on the left, changing the 1 to a 2. So 8 81 = 0.098765432098765432098765…. and therefore 0.0123456790123456790… ∗ 8 = 0.0987654320987654320… and clearly this gets you that 12345679 ∗ 8 = 98765432.
大写123456789怎么写123456789大写分别是：壹、贰、叁、肆、伍、陆、柒、捌、玖。. 1、以中文的形式表示数字，在开具发票、收据的时候经常用到，尤其在金融领域。. 但数字的中文表示和其它语言有很大的不同，如中文以每4.
In the first 1 billion digits of π π, I found two instances of 123456789 123456789, but no instances of 1234567890 1234567890. Here's a simple example. In the first billion digits, there were 10049 10049 instances of 12345. 12345. There were 969 969 instances of 123456 123456. There were 97 97 instances of 1234567 1234567.
31 de dic. de 2019 · $\begingroup$ Some questions which seem a bit related: How can I prove this odd property?, Why is $\frac{987654321}{123456789}$ almost exactly $8$?, Why is $\frac{987654321}{123456789} = 8.0000000729?!$ and maybe some of the questions linked there. $\endgroup$ –
11 de ene. de 2013 · It's not entirely coincidence: 246,913,578 = 2·123,456,789. So of course that's what you get if you multiply by 5 or divide by 2. But I find it surprising that that's what you get if you multiply by 7, and I think there's something else at work here. It's also suspicious that none of those numbers are divisible by 3.
From an old book I found the following question. Use the digits $1,2,3,4,5,6,7,8,9$ and the operations $"+,-,×,÷"$ with $( )$ for construct the result $100.$ During the computations the order of $
20 de ene. de 2017 · 123456789 ∗ 8 = 987654312. The number changes the last two digits, so that division can't be correct. Well, it can't be correct because no number ending in 1 is divisible by 8... You're right, but I thought maybe he wrote wrong the product, so that's why I added this post as an answer.
As an additional note, it is in fact true that the multiples of $123456789$ (note! not $12345679$ which I explained above) that are relatively prime to $9$ also result in a permutation of those digits (including 0 when you reach 10 digits): $$1 \times 123456789 = 123456789$$ $$2 \times 123456789 = 246913578$$ $$4 \times 123456789 = 493827156$$
24 de mar. de 2018 · Then the results of B and C is multiplied and the result is 123456789. What number did A choose? For clarity: Let the number chosen by A be a, the number chosen by B be b, and the number chosen by C be c. We then have: $$(b^2 + a)(c^2\cdot a)= 123456789.$$ How would you solve this problem without a calculator?
