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  1. The 1988 United States presidential election was the 51st quadrennial presidential election held on Tuesday, November 8, 1988. Incumbent Republican Vice President George H. W. Bush defeated the Democratic Massachusetts Governor Michael Dukakis.

  2. In the 1988 presidential election, Republican Vice President George H. W. Bush defeated Democratic Governor Michael Dukakis of Massachusetts. Bush won the popular vote by just under eight points, and won 426 of the 538 electoral votes. Bush won the Republican nomination over Kansas Senator Bob Dole and televangelist Pat Robertson of ...

  3. La elección presidencial de Estados Unidos de 1988 tuvo lugar el martes 8 de noviembre de ese año. La elección de presidente se hace al mismo tiempo que la del vicepresidente, presentándose bajo un mismo "ticket" electoral. También al mismo tiempo se renovó parcialmente el Senado y la Cámara de Representantes al completo.

  4. Eugene McCarthy. Dan Quayle. Lloyd Bentsen. Ron Paul. David Duke. (Show more) United States presidential election of 1988, American presidential election held on Nov. 8, 1988, in which Republican George Bush defeated Democrat Michael Dukakis. The campaign. Michael Dukakis, 1988.

  5. The 1988 United States presidential election in California took place on November 8, 1988, and was part of the 1988 United States presidential election. Voters chose 47 representatives, or electors to the Electoral College, who voted for president and vice president .

  6. Results of the presidential election of 1988, won by George Bush with 426 electoral votes.

  7. The 1988 United States presidential election happened on November 8, 1988. George H. W. Bush , the Republican candidate and Vice President of the United States , won the election. He defeated the Democratic candidate, Governor Michael Dukakis of Massachusetts .