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  1. Grand Duchess Maria Alexandrovna of Russia (Russian: Марія Александровна; 17 October [O.S. 5 October] 1853 – 24 October 1920) was the fifth child and only surviving daughter of Alexander II of Russia and Marie of Hesse and by Rhine; she was Duchess of Edinburgh and later Duchess of Saxe-Coburg and Gotha as the wife of Alfred ...

    • Marie

      e. Maria Alexandrovna (Russian: Мария Александровна ), born...

  2. La Gran Duquesa María Aleksándrovna de Rusia (en ruso: Великая княжна Мария Александровна; Tsárskoye Seló, 17 de octubre de 1853- Zúrich, 24 de octubre de 1920) era la quinta descendiente y única hija sobreviviente del zar Alejandro II de Rusia y de su primera mujer la princesa María de Hesse-Darmstadt. Era ...

  3. Grand Duchess Maria Vladimirovna of Russia (Russian: Мария Владимировна Романова, romanized: Maria Vladimirovna Romanova; born 23 December 1953) has been a claimant to the headship of the House of Romanov, the Imperial Family of Russia (who reigned as Emperors and Autocrats of all the Russias from 1613 to 1917) since 1992.

  4. 13 de may. de 2020 · The present article describes the life of the Grand Duchess Maria Alexandrovna of Russia (1853–1920) through the correspondence with her parents: the Emperor of Russia Alexander II, the Empress and close friends.

  5. Prince Alfred, Queen Victoria’s second son, became engaged to Grand Duchess Maria Alexandrovna, daughter of Russian Emperor Alexander II on 11 July 1873. His mother had misgivings about the match, which she wrote about in her diary: